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Number   :  4331
Date     :  2003-04-17
Author   :  Garry Deane
Subject  :  Re: copy one 1 new file
Size(KB) :  1


--- In xxcopy@yahoogroups.com, "carmenmiller"  
wrote:
> hello all,
> 
> all I want to do is copy the newest file in a folder
> sometime more than 1 file is created on the same day.
> and I want to copy just the newest one to another 
> folder
> 
> thanks
> carmen

Since Xxcopy processes files in the "natural" disk order and it 
doesn't accept source files from an input list (sigh), you need 
another method to get the newest file. Typically you'd use a batch 
file to create a DIR listing in reverse date order, get the first 
file name from the list then copy that file. Below are a couple of 
example batch files assuming a copy from d:\test\*.txt to e:\test for 
the newest file less than 1 day old. Obviously adjust the file spec 
to suit your needs. The W9x/ME version uses a utility called LMOD but 
you could use other similar programs to do the same thing.

Garry

@echo off
:: NT/W2k/XP version
setlocal
pushd d:\test
for /f "tokens=*" %%a in ('dir /b/o-d *.txt') do (
set file="%%a"&goto :copy)
:copy
xxcopy %file% e:\test /po0/bi/da#1
goto :eof


@echo off
:: W9x/ME version using LMOD
:: http://home.mnet-online.de/horst.muc/
d:
cd d:\test
dir /b/o-d *.txt|lmod set file="[]" > %temp%\tmpcopy.bat
for %%a in (call del) do %%a %temp%\tmpcopy.bat
xxcopy %file% e:\test /po0/bi/da#1
set file=
cd \



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